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2y^2-22y-52=0
a = 2; b = -22; c = -52;
Δ = b2-4ac
Δ = -222-4·2·(-52)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-30}{2*2}=\frac{-8}{4} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+30}{2*2}=\frac{52}{4} =13 $
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